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Common Compiler-Supported C++ Variable Types

In most of the examples thus far, you have defined variables of typeint—that is, integers. However, C++ programmers can choose from a variety of fundamental variable types supported directly by the compiler. Choosing the right variable type is important. An integer cannot be used to store values that contain decimals without loss of decimal data. If your program needs to store the value of pi, for instance, you can use the typefloatordouble. Table 3.1 lists the various variable types and the data values they can contain.

TABLE 3.1Variable Types

Type

Values

bool

trueorfalse

char

256 character values

unsigned short int

0 to 65,535

short int

–32,768 to 32,767

unsigned long int

0 to 4,294,967,295

long int

–2,147,483,648 to 2,147,483,647

unsigned long long

0 to 18,446,744,073,709,551,615

long long

–9,223,372,036,854,775,808 to 9,223,372,036,854,775,807

int(16 bit)

–32,768 to 32,767

int(32 bit)

–2,147,483,648 to 2,147,483,647

unsigned int(16 bit)

0 to 65,535

unsigned int(32 bit)

0 to 4,294,967,295

float

1.2e–38 to 3.4e38

double

2.2e–308 to 1.8e308

long double

2.2e–308 to 1.8e308

(This is the same as adoublevariable type on Microsoft Visual C++ [MSVC] but is supported differently on other platforms.)

The following sections explain the important variable types in greater detail.

Using Typeboolto Store Boolean Values

C++ provides a typeboolthat is specially created for containing Boolean valuestrueorfalse, both of which are reserved words.

Typeboolis particularly useful for storing settings and flags that can be on or off, present or absent, available or unavailable, and the like.

A sample declaration of an initialized Boolean variable is

bool alwaysOn = true;

An expression that evaluates to a Boolean type is

bool deleteFile = (userSelection == "yes"); // evaluates to true if userSelection contains "yes", else to false

Conditional expressions are explained in Lesson 5, “Working with Expressions, Statements, and Operators.”

Using Typecharto Store Character Values

You use typecharto store a single character. A sample declaration is

char userInput = 'Y'; // initialized char to 'Y'

Memory is composed of bits and bytes. Bits evaluate to either state 0 or state 1. Bytes are the smallest unit of memory and comprise bits: 1 byte contains 8 bits. Thus bytes contain numeric data in binary format. When a program uses character data as shown in the example above, the compiler converts the character into a numeric representation that can be placed into memory. The numeric representation of Latin characters A–Z, a–z, numbers 0–9, some special keystrokes (for example, DEL), and special characters (such as backspace) has been standardized by the American Standard Code for Information Interchange, also called ASCII.

You can look up the table in Appendix D, “ASCII Codes,” to see that the character Y assigned to variableuserInputhas the ASCII value89in decimal or01011001in binary. Thus, the compiler stores01011001in the memory space allocated foruserInput.

The Concept of Signed and Unsigned Integers

Signimplies positive or negative. All numbers you work with using a computer are stored in memory in the form of bits and bytes. A memory location that is 1 byte in size contains 8 bits. Each bit can either be a 0 or 1 (that is, carry one of these two values, at best). Thus, a memory location that is 1 byte in size can contain a maximum of 2 to the power 8 values—that is, 256 unique values. Similarly, a memory location that is 16 bits in size can contain 2 to the power 16 values—that is, 65,536 unique values.

If these values were to be unsigned—that is, assumed to be only positive—then 1 byte could contain integer values ranging from 0 through 255, and 2 bytes could contain values ranging from 0 through 65,535. Referring to Table 3.1, you’ll note thatunsigned shortis the type that supports this range and comprises 16 bits. Thus, it is quite easy to model positive values in bits and bytes (seeFigure 3.1).

FIGURE 3.1

FIGURE 3.1Organization of bits in a 16-bit unsigned short integer.

How do you model negative numbers in this space? One way is to “sacrifice” a bit as the sign bit that indicates whether the values contained in the other bits are positive or negative (seeFigure 3.2). The sign bit needs to be the most-significant-bit (MSB) as the least-significant-bit is required for storing odd numbers. So, when the MSB contains sign information, it is assumed that 0 is positive and 1 means negative, and the other bytes contain the absolute value.

FIGURE 3.2

FIGURE 3.2Organization of bits in a 16-bit signed short integer.

Thus, a signed number that stores 16 bits can contain values ranging from –32,768 through 32,767, and one that stores 8 bits can contain values ranging from –128 through 127. If you look at Table 3.1 again, note that (signed)shortis the type that supports positive and negative integer values in a 16-bit space.

带符号整数Typesshort,int,long, andlong long

Integer typesshort,int,long, andlong longdiffer in their sizes and the range of values they can contain.intis possibly the most used type and is 32 bits wide on most compilers. It is important to use the right type, based on your projection of the maximum value that a particular variable would be expected to hold.

Declaring a variable of a signed type is simple:

short int gradesInMath = -5; // not your best score int moneyInBank = -70000; // overdraft long populationChange = -85000; // reducing population long long countryGDP_YoY = -70000000000; // GDP lower by 70 billion

Unsigned Integer Typesunsigned short,unsigned int,unsigned long, andunsigned long long

Unlike their signed counterparts, unsigned integer variable types have not sacrificed a bit to store sign information, and therefore they support twice as many positive values.

Declaring a variable of an unsigned type is as simple as this:

unsigned short int numColorsInRainbow = 7; unsigned int numEggsInBasket = 24; // will always be positive unsigned long numCarsInNewYork = 700000; unsigned long long countryMedicareExpense = 70000000000;

避免溢出错误通过选择正确的数据Types

Data types such asshort,int,long,unsigned short,unsigned int,unsigned long, and the like have a finite capacity for containing numbers. When you exceed the limit imposed by the type chosen in an arithmetic operation, you create an overflow.

Takeunsigned shortas an example. Data typeshortconsumes 16 bits and can hence contain values from 0 through 65,535. When you add 1 to 65,535 in anunsigned short, the value overflows to 0. It’s like the odometer of a car that suffers a mechanical overflow when it can support only five digits and the car has traveled 99,999 kilometers (or miles).

In this case,unsigned shortwas never the right type for such a counter. The programmer would have been better off usingunsigned intto support numbers higher than 65,535.

In the case of asigned shortinteger, which has a range of –32,768 through 32,767, adding 1 to 32,767 may result in thesigned integertaking the highest negative value. This behavior is compiler dependent.

清单3.4演示了溢出错误you can inadvertently introduce via arithmetic operations.

Input
Listing 3.4Examples of the Ill Effects of Signed and Unsigned Integer Overflow Errors

1: #include 2: using namespace std; 3: 4: int main() 5: { 6: unsigned short uShortValue = 65535; 7: cout << "unsigned short 65535 + 1 = "; 8: cout << ++uShortValue << endl; 9: 10: short signedShort = 32767; 11: cout << "signed short 32767 + 1 = "; 12: cout << ++signedShort << endl; 13: 14: return 0; 15: }

Output

unsigned short 65535 + 1 = 0 signed short 32767 + 1 = -32768

Analysis

The output indicates that unintentional overflow situations result in unpredictable and unintuitive behavior for the application. Lines 8 and 12 increment anunsigned shortand asigned shortthat have previously been initialized to their maximum supported values, –65,535 and 32,767, respectively. The output demonstrates the values the integers hold after the increment operation—namely an overflow of 65,535 to 0 in theunsigned shortand an overflow of 32,767 to –32,768 in thesigned short. You wouldn’t expect the result of an increment operation to reduce the value in question, but that is exactly what happens when an integer type overflows. If you were using the values in question to allocate memory, then with theunsigned short, you could reach a point where you would request 0 bytes when your actual need is 65,536 bytes.

Floating-Point Typesfloatanddouble

Floating-point types are used to storereal numbers—that is, numbers that can be positive or negative and that can contain decimal values. So, if you want to store the value of pi (22 / 7, or 3.14) in a variable in C++, you use a floating-point type.

Declaring variables of these types follows exactly the same pattern as theintin Listing 3.1. So, afloatthat allows you to store decimal values would be declared as

float pi = 3.14;

And a double precisionfloat(called simply adouble) is defined as

double morePrecisePi = 22.0 / 7;

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